
// 统计不重复元素个数的算法
pub fn new_count_distinct(input_str: &str) -> usize {
    let mut values = vec![];
    let value = input_str.split(",");
    for v in value {
        if !values.contains(&v) {
            values.push(v);
        }
    }
    values.len()
    
}
